-16t^2+95t+0=114

Solution for -16t^2+95t+0=114 equation:

-16t^2+95t+0=114

We move all terms to the left:

-16t^2+95t+0-(114)=0

We add all the numbers together, and all the variables

-16t^2+95t-114=0

a = -16; b = 95; c = -114;
Δ = b2-4ac
Δ = 952-4·(-16)·(-114)
Δ = 1729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(95)-\sqrt{1729}}{2*-16}=\frac{-95-\sqrt{1729}}{-32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(95)+\sqrt{1729}}{2*-16}=\frac{-95+\sqrt{1729}}{-32}
$